/* Analyze file differences for GNU DIFF.
   Copyright (C) 1988, 1989, 1992, 1993 Free Software Foundation, Inc.

This file is part of GNU DIFF.

GNU DIFF is free software; you can redistribute it and/or modify
it under the terms of the GNU General Public License as published by
the Free Software Foundation; either version 2, or (at your option)
any later version.

GNU DIFF is distributed in the hope that it will be useful,
but WITHOUT ANY WARRANTY; without even the implied warranty of
MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE.  See the
GNU General Public License for more details.

You should have received a copy of the GNU General Public License
along with GNU DIFF; see the file COPYING.  If not, write to
the Free Software Foundation, 675 Mass Ave, Cambridge, MA 02139, USA.  */

/* The basic algorithm is described in:
   "An O(ND) Difference Algorithm and its Variations", Eugene Myers,
   Algorithmica Vol. 1 No. 2, 1986, pp. 251-266;
   see especially section 4.2, which describes the variation used below.

   Unless the --minimal option is specified, this code uses the TOO_EXPENSIVE
   heuristic, by Paul Eggert, to limit the cost to O(N**1.5 log N)
   at the price of producing suboptimal output for large inputs with
   many differences.  Related algorithms are surveyed by Alfred V. Aho in
   section 6.3 of 'Algorithms for Finding Patterns in Strings',
   Handbook of Theoretical Computer Science (Jan Van Leeuwen,
   ed.), Vol. A, Algorithms and Complexity, Elsevier/MIT Press,
   1990, pp. 255--300.

   The basic algorithm was independently discovered as described in:
   "Algorithms for Approximate String Matching", Esko Ukkonen,
   Information and Control Vol. 64, 1985, pp. 100-118.  
*/

#include "diff.h"
#include "cmpbuf.h"
#include <assert.h>
#ifdef _WIN32
#  include <io.h>
#endif

DECL_TLS int no_discards;
DECL_TLS int need_free_buffers=0;

static DECL_TLS int *xvec, *yvec;	/* Vectors being compared. */
static DECL_TLS int *fdiag;		/* Vector, indexed by diagonal, containing
				   1 + the X coordinate of the point furthest
				   along the given diagonal in the forward
				   search of the edit matrix. */
static DECL_TLS int *bdiag;		/* Vector, indexed by diagonal, containing
				   the X coordinate of the point furthest
				   along the given diagonal in the backward
				   search of the edit matrix. */
static DECL_TLS int too_expensive;	/* Edit scripts longer than this are too
				   expensive to compute.  */

#define SNAKE_LIMIT 20	/* Snakes bigger than this are considered `big'.  */

struct partition
{
  int xmid, ymid;	/* Midpoints of this partition.  */
  int lo_minimal;	/* Nonzero if low half will be analyzed minimally.  */
  int hi_minimal;	/* Likewise for high half.  */
};

static int diag (int, int, int, int, int, struct partition *);
static struct change *add_change (int, int, int, int, struct change *);
static struct change *build_reverse_script (struct file_data const[]);
static struct change *build_script (struct file_data const[]);
static void briefly_report (int, struct file_data const[]);
static void compareseq (int, int, int, int, int);
static void discard_confusing_lines (struct file_data[]);
static void shift_boundaries (struct file_data[]);

/* Find the midpoint of the shortest edit script for a specified
   portion of the two files.

   Scan from the beginnings of the files, and simultaneously from the ends,
   doing a breadth-first search through the space of edit-sequence.
   When the two searches meet, we have found the midpoint of the shortest
   edit sequence.

   If MINIMAL is nonzero, find the minimal edit script regardless
   of expense.  Otherwise, if the search is too expensive, use
   heuristics to stop the search and report a suboptimal answer.

   Set PART->(XMID,YMID) to the midpoint (XMID,YMID).  The diagonal number
   XMID - YMID equals the number of inserted lines minus the number
   of deleted lines (counting only lines before the midpoint).
   Return the approximate edit cost; this is the total number of
   lines inserted or deleted (counting only lines before the midpoint),
   unless a heuristic is used to terminate the search prematurely.

   Set PART->LEFT_MINIMAL to nonzero iff the minimal edit script for the
   left half of the partition is known; similarly for PART->RIGHT_MINIMAL.

   This function assumes that the first lines of the specified portions
   of the two files do not match, and likewise that the last lines do not
   match.  The caller must trim matching lines from the beginning and end
   of the portions it is going to specify.

   If we return the "wrong" partitions,
   the worst this can do is cause suboptimal diff output.
   It cannot cause incorrect diff output.  */

static int
diag (int xoff, int xlim, int yoff, int ylim, int minimal, struct partition *part)
{
  int *const fd = fdiag;	/* Give the compiler a chance. */
  int *const bd = bdiag;	/* Additional help for the compiler. */
  int const *const xv = xvec;	/* Still more help for the compiler. */
  int const *const yv = yvec;	/* And more and more . . . */
  int const dmin = xoff - ylim;	/* Minimum valid diagonal. */
  int const dmax = xlim - yoff;	/* Maximum valid diagonal. */
  int const fmid = xoff - yoff;	/* Center diagonal of top-down search. */
  int const bmid = xlim - ylim;	/* Center diagonal of bottom-up search. */
  int fmin = fmid, fmax = fmid;	/* Limits of top-down search. */
  int bmin = bmid, bmax = bmid;	/* Limits of bottom-up search. */
  int c;			/* Cost. */
  int odd = (fmid - bmid) & 1;	/* True if southeast corner is on an odd
				   diagonal with respect to the northwest. */

  fd[fmid] = xoff;
  bd[bmid] = xlim;

  for (c = 1;; ++c)
    {
      int d;			/* Active diagonal. */
      int big_snake = 0;

      /* Extend the top-down search by an edit step in each diagonal. */
      fmin > dmin ? fd[--fmin - 1] = -1 : ++fmin;
      fmax < dmax ? fd[++fmax + 1] = -1 : --fmax;
      for (d = fmax; d >= fmin; d -= 2)
	{
	  int x, y, oldx, tlo = fd[d - 1], thi = fd[d + 1];

	  if (tlo >= thi)
	    x = tlo + 1;
	  else
	    x = thi;
	  oldx = x;
	  y = x - d;
	  while (x < xlim && y < ylim && xv[x] == yv[y])
	    ++x, ++y;
	  if (x - oldx > SNAKE_LIMIT)
	    big_snake = 1;
	  fd[d] = x;
	  if (odd && bmin <= d && d <= bmax && bd[d] <= x)
	    {
	      part->xmid = x;
	      part->ymid = y;
	      part->lo_minimal = part->hi_minimal = 1;
	      return 2 * c - 1;
	    }
	}

      /* Similarly extend the bottom-up search.  */
      bmin > dmin ? bd[--bmin - 1] = INT_MAX : ++bmin;
      bmax < dmax ? bd[++bmax + 1] = INT_MAX : --bmax;
      for (d = bmax; d >= bmin; d -= 2)
	{
	  int x, y, oldx, tlo = bd[d - 1], thi = bd[d + 1];

	  if (tlo < thi)
	    x = tlo;
	  else
	    x = thi - 1;
	  oldx = x;
	  y = x - d;
	  while (x > xoff && y > yoff && xv[x - 1] == yv[y - 1])
	    --x, --y;
	  if (oldx - x > SNAKE_LIMIT)
	    big_snake = 1;
	  bd[d] = x;
	  if (!odd && fmin <= d && d <= fmax && x <= fd[d])
	    {
	      part->xmid = x;
	      part->ymid = y;
	      part->lo_minimal = part->hi_minimal = 1;
	      return 2 * c;
	    }
	}

      if (minimal)
	continue;

      /* Heuristic: check occasionally for a diagonal that has made
	 lots of progress compared with the edit distance.
	 If we have any such, find the one that has made the most
	 progress and return it as if it had succeeded.

	 With this heuristic, for files with a constant small density
	 of changes, the algorithm is linear in the file size.  */

      if (c > 200 && big_snake && heuristic)
	{
	  int best;

	  best = 0;
	  for (d = fmax; d >= fmin; d -= 2)
	    {
	      int dd = d - fmid;
	      int x = fd[d];
	      int y = x - d;
	      int v = (x - xoff) * 2 - dd;
	      if (v > 12 * (c + (dd < 0 ? -dd : dd)))
		{
		  if (v > best
		      && xoff + SNAKE_LIMIT <= x && x < xlim
		      && yoff + SNAKE_LIMIT <= y && y < ylim)
		{
		      /* We have a good enough best diagonal;
			 now insist that it end with a significant snake.  */
		      int k;

		      for (k = 1; xv[x - k] == yv[y - k]; k++)
			if (k == SNAKE_LIMIT)
			{
			    best = v;
			    part->xmid = x;
			    part->ymid = y;
			    break;
			}
		    }
		}
	    }
	  if (best > 0)
	    {
	      part->lo_minimal = 1;
	      part->hi_minimal = 0;
	      return 2 * c - 1;
	    }

	  best = 0;
	  for (d = bmax; d >= bmin; d -= 2)
	    {
	      int dd = d - bmid;
	      int x = bd[d];
	      int y = x - d;
	      int v = (xlim - x) * 2 + dd;
	      if (v > 12 * (c + (dd < 0 ? -dd : dd)))
		{
		  if (v > best
		      && xoff < x && x <= xlim - SNAKE_LIMIT
		      && yoff < y && y <= ylim - SNAKE_LIMIT)
		{
		      /* We have a good enough best diagonal;
			 now insist that it end with a significant snake.  */
		      int k;

		      for (k = 0; xv[x + k] == yv[y + k]; k++)
			if (k == SNAKE_LIMIT - 1)
			  {
			    best = v;
			    part->xmid = x;
			    part->ymid = y;
			  break;
			  }
		    }
		}
	    }
	  if (best > 0)
	    {
	      part->lo_minimal = 0;
	      part->hi_minimal = 1;
	      return 2 * c - 1;
	    }
	}

      /* Heuristic: if we've gone well beyond the call of duty,
	 give up and report halfway between our best results so far.  */
      if (c >= too_expensive)
	{
	  int fxybest, fxbest;
	  int bxybest, bxbest;

	  fxbest = bxbest = 0;  /* Pacify `gcc -Wall'.  */

	  /* Find forward diagonal that maximizes X + Y.  */
	  fxybest = -1;
	  for (d = fmax; d >= fmin; d -= 2)
	    {
	      int x = min (fd[d], xlim);
	      int y = x - d;
	      if (ylim < y)
		x = ylim + d, y = ylim;
	      if (fxybest < x + y)
			{
		  fxybest = x + y;
		  fxbest = x;
			}
		    }

	  /* Find backward diagonal that minimizes X + Y.  */
	  bxybest = INT_MAX;
	  for (d = bmax; d >= bmin; d -= 2)
	    {
	      int x = max (xoff, bd[d]);
	      int y = x - d;
	      if (y < yoff)
		x = yoff + d, y = yoff;
	      if (x + y < bxybest)
		{
		  bxybest = x + y;
		  bxbest = x;
		}
		}

	  /* Use the better of the two diagonals.  */
	  if ((xlim + ylim) - bxybest < fxybest - (xoff + yoff))
	    {
	      part->xmid = fxbest;
	      part->ymid = fxybest - fxbest;
	      part->lo_minimal = 1;
	      part->hi_minimal = 0;
	    }
	  else
	    {
	      part->xmid = bxbest;
	      part->ymid = bxybest - bxbest;
	      part->lo_minimal = 0;
	      part->hi_minimal = 1;
	    }
	  return 2 * c - 1;
	}
    }
}

/* Compare in detail contiguous subsequences of the two files
   which are known, as a whole, to match each other.

   The results are recorded in the vectors files[N].changed_flag, by
   storing a 1 in the element for each line that is an insertion or deletion.

   The subsequence of file 0 is [XOFF, XLIM) and likewise for file 1.

   Note that XLIM, YLIM are exclusive bounds.
   All line numbers are origin-0 and discarded lines are not counted.

   If MINIMAL is nonzero, find a minimal difference no matter how
   expensive it is.  */

static void
compareseq (int xoff, int xlim, int yoff, int ylim, int minimal)
{
  int * const xv = xvec; /* Help the compiler.  */
  int * const yv = yvec;

  /* Slide down the bottom initial diagonal. */
  while (xoff < xlim && yoff < ylim && xv[xoff] == yv[yoff])
    ++xoff, ++yoff;
  /* Slide up the top initial diagonal. */
  while (xlim > xoff && ylim > yoff && xv[xlim - 1] == yv[ylim - 1])
    --xlim, --ylim;

  /* Handle simple cases. */
  if (xoff == xlim)
    while (yoff < ylim)
      files[1].changed_flag[files[1].realindexes[yoff++]] = 1;
  else if (yoff == ylim)
    while (xoff < xlim)
      files[0].changed_flag[files[0].realindexes[xoff++]] = 1;
  else
    {
      int c;
      struct partition part;

      /* Find a point of correspondence in the middle of the files.  */

      c = diag (xoff, xlim, yoff, ylim, minimal, &part);

      if (c == 1)
	{
	  /* This should be impossible, because it implies that
	     one of the two subsequences is empty,
	     and that case was handled above without calling `diag'.
	     Let's verify that this is true.  */
	  abort ();
#if 0
	  /* The two subsequences differ by a single insert or delete;
	     record it and we are done.  */
	  if (part.xmid - part.ymid < xoff - yoff)
	    files[1].changed_flag[files[1].realindexes[part.ymid - 1]] = 1;
	  else
	    files[0].changed_flag[files[0].realindexes[part.xmid]] = 1;
#endif
	}
      else
	{
	  /* Use the partitions to split this problem into subproblems.  */
	  compareseq (xoff, part.xmid, yoff, part.ymid, part.lo_minimal);
	  compareseq (part.xmid, xlim, part.ymid, ylim, part.hi_minimal);
	}
    }
}

/* Discard lines from one file that have no matches in the other file.

   A line which is discarded will not be considered by the actual
   comparison algorithm; it will be as if that line were not in the file.
   The file's `realindexes' table maps virtual line numbers
   (which don't count the discarded lines) into real line numbers;
   this is how the actual comparison algorithm produces results
   that are comprehensible when the discarded lines are counted.

   When we discard a line, we also mark it as a deletion or insertion
   so that it will be printed in the output.  */

static void
discard_confusing_lines (struct file_data filevec[])
{
  unsigned int f, i;
  char *discarded[2];
  int *equiv_count[2];
  int *p;

  /* Allocate our results.  */
  p = (int *) xmalloc ((filevec[0].buffered_lines + filevec[1].buffered_lines)
		       * (2 * sizeof (int)));
  for (f = 0; f < 2; f++)
    {
      filevec[f].undiscarded = p;  p += filevec[f].buffered_lines;
      filevec[f].realindexes = p;  p += filevec[f].buffered_lines;
    }

  /* Set up equiv_count[F][I] as the number of lines in file F
     that fall in equivalence class I.  */

  p = (int *) xmalloc (filevec[0].equiv_max * (2 * sizeof (int)));
  equiv_count[0] = p;
  equiv_count[1] = p + filevec[0].equiv_max;
  bzero (p, filevec[0].equiv_max * (2 * sizeof (int)));

  for (i = 0; i < (unsigned int)filevec[0].buffered_lines; ++i)
    ++equiv_count[0][filevec[0].equivs[i]];
  for (i = 0; i < (unsigned int)filevec[1].buffered_lines; ++i)
    ++equiv_count[1][filevec[1].equivs[i]];

  /* Set up tables of which lines are going to be discarded.  */

  discarded[0] = xmalloc (sizeof (char)
			  * (filevec[0].buffered_lines
			     + filevec[1].buffered_lines));
  discarded[1] = discarded[0] + filevec[0].buffered_lines;
  bzero (discarded[0], sizeof (char) * (filevec[0].buffered_lines
					+ filevec[1].buffered_lines));

  /* Mark to be discarded each line that matches no line of the other file.
     If a line matches many lines, mark it as provisionally discardable.  */

  for (f = 0; f < 2; f++)
    {
      unsigned int end = filevec[f].buffered_lines;
      char *discards = discarded[f];
      int *counts = equiv_count[1 - f];
      int *equivs = filevec[f].equivs;
      unsigned int many = 5;
      unsigned int tem = end / 64;

      /* Multiply MANY by approximate square root of number of lines.
	 That is the threshold for provisionally discardable lines.  */
      while ((tem = tem >> 2) > 0)
	many *= 2;

      for (i = 0; i < end; i++)
	{
	  int nmatch;
	  if (equivs[i] == 0)
	    continue;
	  nmatch = counts[equivs[i]];
	  if (nmatch == 0)
	    discards[i] = 1;
	  else if (nmatch > (int)many)
	    discards[i] = 2;
	}
    }

  /* Don't really discard the provisional lines except when they occur
     in a run of discardables, with nonprovisionals at the beginning
     and end.  */

  for (f = 0; f < 2; f++)
    {
      unsigned int end = filevec[f].buffered_lines;
      register char *discards = discarded[f];

      for (i = 0; i < end; i++)
	{
	  /* Cancel provisional discards not in middle of run of discards.  */
	  if (discards[i] == 2)
	    discards[i] = 0;
	  else if (discards[i] != 0)
	    {
	      /* We have found a nonprovisional discard.  */
	      register int j;
	      unsigned int length;
	      unsigned int provisional = 0;

	      /* Find end of this run of discardable lines.
		 Count how many are provisionally discardable.  */
	      for (j = (int)i; (unsigned int)j < end; j++)
		{
		  if (discards[j] == 0)
		    break;
		  if (discards[j] == 2)
		    ++provisional;
		}

	      /* Cancel provisional discards at end, and shrink the run.  */
	      while (j > (int)i && discards[j - 1] == 2)
		discards[--j] = 0, --provisional;

	      /* Now we have the length of a run of discardable lines
		 whose first and last are not provisional.  */
	      length = j - i;

	      /* If 1/4 of the lines in the run are provisional,
		 cancel discarding of all provisional lines in the run.  */
	      if (provisional * 4 > length)
		{
		  while (j > (int)i)
		    if (discards[--j] == 2)
		      discards[j] = 0;
		}
	      else
		{
		  register unsigned int consec;
		  unsigned int minimum = 1;
		  unsigned int tem = length / 4;

		  /* MINIMUM is approximate square root of LENGTH/4.
		     A subrun of two or more provisionals can stand
		     when LENGTH is at least 16.
		     A subrun of 4 or more can stand when LENGTH >= 64.  */
		  while ((tem = tem >> 2) > 0)
		    minimum *= 2;
		  minimum++;

		  /* Cancel any subrun of MINIMUM or more provisionals
		     within the larger run.  */
		  for (j = 0, consec = 0; (unsigned int)j < length; j++)
		    if (discards[i + j] != 2)
		      consec = 0;
		    else if (minimum == ++consec)
		      /* Back up to start of subrun, to cancel it all.  */
		      j -= consec;
		    else if (minimum < consec)
		      discards[i + j] = 0;

		  /* Scan from beginning of run
		     until we find 3 or more nonprovisionals in a row
		     or until the first nonprovisional at least 8 lines in.
		     Until that point, cancel any provisionals.  */
		  for (j = 0, consec = 0; (unsigned int)j < length; j++)
		    {
		      if (j >= 8 && discards[i + j] == 1)
			break;
		      if (discards[i + j] == 2)
			consec = 0, discards[i + j] = 0;
		      else if (discards[i + j] == 0)
			consec = 0;
		      else
			consec++;
		      if (consec == 3)
			break;
		    }

		  /* I advances to the last line of the run.  */
		  i += length - 1;

		  /* Same thing, from end.  */
		  for (j = 0, consec = 0; (unsigned int)j < length; j++)
		    {
		      if (j >= 8 && discards[i - j] == 1)
			break;
		      if (discards[i - j] == 2)
			consec = 0, discards[i - j] = 0;
		      else if (discards[i - j] == 0)
			consec = 0;
		      else
			consec++;
		      if (consec == 3)
			break;
		    }
		}
	    }
	}
    }

  /* Actually discard the lines. */
  for (f = 0; f < 2; f++)
    {
      char *discards = discarded[f];
      unsigned int end = filevec[f].buffered_lines;
      unsigned int j = 0;
      for (i = 0; i < end; ++i)
	if (no_discards || discards[i] == 0)
	  {
	    filevec[f].undiscarded[j] = filevec[f].equivs[i];
	    filevec[f].realindexes[j++] = i;
	  }
	else
	  filevec[f].changed_flag[i] = 1;
      filevec[f].nondiscarded_lines = j;
    }

  free (discarded[0]);
  free (equiv_count[0]);
}

/* Adjust inserts/deletes of identical lines to join changes
   as much as possible.

   We do something when a run of changed lines include a
   line at one end and have an excluded, identical line at the other.
   We are free to choose which identical line is included.
   `compareseq' usually chooses the one at the beginning,
   but usually it is cleaner to consider the following identical line
   to be the "change".  */

DECL_TLS int inhibit;

static void
shift_boundaries (struct file_data filevec[])
{
  int f;

  if (inhibit)
    return;

  for (f = 0; f < 2; f++)
    {
      char *changed = filevec[f].changed_flag;
      char const *other_changed = filevec[1-f].changed_flag;
      int const *equivs = filevec[f].equivs;
      int i = 0;
      int j = 0;
      int i_end = filevec[f].buffered_lines;

      while (1)
	{
	  int runlength, start, corresponding;

	  /* Scan forwards to find beginning of another run of changes.
	     Also keep track of the corresponding point in the other file.  */

	  while (i < i_end && changed[i] == 0)
	    {
	      while (other_changed[j++])
		continue;
	      i++;
	    }

	  if (i == i_end)
	    break;

	  start = i;

	  /* Find the end of this run of changes.  */

	  while (changed[++i])
	    continue;
	  while (other_changed[j])
	    j++;

	  do
	    {
	      /* Record the length of this run of changes, so that
		 we can later determine whether the run has grown.  */
	      runlength = i - start;

	      /* Move the changed region back, so long as the
		 previous unchanged line matches the last changed one.
		 This merges with previous changed regions.  */

	      while (start && equivs[start - 1] == equivs[i - 1])
		{
		  changed[--start] = 1;
		  changed[--i] = 0;
		  while (changed[start - 1])
		    start--;
		  while (other_changed[--j])
		    continue;
		}

	      /* Set CORRESPONDING to the end of the changed run, at the last
		 point where it corresponds to a changed run in the other file.
		 CORRESPONDING == I_END means no such point has been found.  */
	      corresponding = other_changed[j - 1] ? i : i_end;

	      /* Move the changed region forward, so long as the
		 first changed line matches the following unchanged one.
		 This merges with following changed regions.
		 Do this second, so that if there are no merges,
		 the changed region is moved forward as far as possible.  */

	      while (i != i_end && equivs[start] == equivs[i])
		{
		  changed[start++] = 0;
		  changed[i++] = 1;
		  while (changed[i])
		    i++;
		  while (other_changed[++j])
		    corresponding = i;
		}
	    }
	  while (runlength != i - start);

	  /* If possible, move the fully-merged run of changes
	     back to a corresponding run in the other file.  */

	  while (corresponding < i)
	    {
	      changed[--start] = 1;
	      changed[--i] = 0;
	      while (other_changed[--j])
		continue;
	}
    }
}
}

/* Cons an additional entry onto the front of an edit script OLD.
   LINE0 and LINE1 are the first affected lines in the two files (origin 0).
   DELETED is the number of lines deleted here from file 0.
   INSERTED is the number of lines inserted here in file 1.

   If DELETED is 0 then LINE0 is the number of the line before
   which the insertion was done; vice versa for INSERTED and LINE1.  */

static struct change *
add_change (int line0, int line1, int deleted, int inserted, struct change *old)
{
  struct change *newob = (struct change *) xmalloc (sizeof (struct change));
  memset(newob, 0, sizeof(*newob));

  newob->line0 = line0;
  newob->line1 = line1;
  newob->inserted = inserted;
  newob->deleted = deleted;
  newob->link = old;
  newob->match0 = -1; /* WinMerge moved block code */
  newob->match1 = -1; /* WinMerge moved block code */
  return newob;
}

/* Scan the tables of which lines are inserted and deleted,
   producing an edit script in reverse order.  */

static struct change *
build_reverse_script (struct file_data const filevec[])
{
  struct change *script = NULL;
  char *changed0 = filevec[0].changed_flag;
  char *changed1 = filevec[1].changed_flag;
  int len0 = filevec[0].buffered_lines;
  int len1 = filevec[1].buffered_lines;

  /* Note that changedN[len0] does exist, and contains 0.  */

  int i0 = 0, i1 = 0;

  while (i0 < len0 || i1 < len1)
    {
      if (changed0[i0] || changed1[i1])
	{
	  int line0 = i0, line1 = i1;

	  /* Find # lines changed here in each file.  */
	  while (changed0[i0]) ++i0;
	  while (changed1[i1]) ++i1;

	  /* Record this change.  */
	  script = add_change (line0, line1, i0 - line0, i1 - line1, script);
	}

      /* We have reached lines in the two files that match each other.  */
      i0++, i1++;
    }

  return script;
}

/* Scan the tables of which lines are inserted and deleted,
   producing an edit script in forward order.  */

static struct change *
build_script (struct file_data const filevec[])
{
  struct change *script = NULL;
  char *changed0 = filevec[0].changed_flag;
  char *changed1 = filevec[1].changed_flag;
  int i0 = filevec[0].buffered_lines, i1 = filevec[1].buffered_lines;

  /* Note that changedN[-1] does exist, and contains 0.  */

  while (i0 >= 0 || i1 >= 0)
    {
      if (changed0[i0 - 1] || changed1[i1 - 1])
	{
	  int line0 = i0, line1 = i1;

	  /* Find # lines changed here in each file.  */
	  while (changed0[i0 - 1]) --i0;
	  while (changed1[i1 - 1]) --i1;

	  /* Record this change.  */
	  script = add_change (i0, i1, line0 - i0, line1 - i1, script);
	}

      /* We have reached lines in the two files that match each other.  */
      i0--, i1--;
    }

  return script;
}

/* If CHANGES, briefly report that two files differed.  */
static void
briefly_report (int changes, struct file_data const filevec[])
{
  if (changes)
    message (no_details_flag ? "Files %s and %s differ\n"
	     : "Binary files %s and %s differ\n",
	     filevec[0].name, filevec[1].name);
}

//  Report the differences of two files.  DEPTH is the current directory
// depth. 
// WinMerge: add bMoved_blocks_flag for detecting moved blocks and
// bin_file for getting info which file is binary file (can be NULL)
// Winmerge: assume S_ISREG() files, not pipes, directories or devices
struct change * diff_2_files (struct file_data filevec[], int depth, int * bin_status,
	int bMoved_blocks_flag, int * bin_file)
{
	int diags;
	int i;
	struct change *script=NULL;
	int changes;
	
	
	//  If we have detected that either file is binary,
	// compare the two files as binary.  This can happen
	// only when the first chunk is read.
	// Also, --brief without any --ignore-* options means
	// we can speed things up by treating the files as binary.  
	if (read_files (filevec, no_details_flag & ~ignore_some_changes, bin_file))
	{
		//  We can now safely assume to have a pair of Binary files.

		// Are both files Open and Regular (no Pipes, Directories, Devices (e.g. NUL))
		if (filevec[0].desc < 0 || filevec[1].desc < 0 ||
			!(S_ISREG (filevec[0].stat.st_mode)) || !(S_ISREG (filevec[1].stat.st_mode))   )
			changes = 1;
		else
		//  Files with different lengths must be different.  
		if (filevec[0].stat.st_size != filevec[1].stat.st_size)
			changes = 1;
		else
		//  Identical descriptor implies identical files
		if (filevec[0].desc == filevec[1].desc)
			changes = 0;
		//  Scan both files, a buffer at a time, looking for a difference.  
		else
		{
			//  Same-sized buffers for both files were allocated in read_files().  
			size_t buffer_size = filevec[0].bufsize;
			
			for (;;)
			{
				//  Read a buffer's worth from both files.  
				for (i = 0; i < 2; i++)
					while (filevec[i].buffered_chars < buffer_size)
					  {
						int r = _read (filevec[i].desc,
									   filevec[i].buffer	+ filevec[i].buffered_chars,
									   (int)(buffer_size - filevec[i].buffered_chars));
						if (r == 0)
							break;
						if (r < 0)
							pfatal_with_name (filevec[i].name);
						filevec[i].buffered_chars += r;
					  }
						
				//  If the buffers have different number of chars, the files differ.  
				if (filevec[0].buffered_chars != filevec[1].buffered_chars)
				{
					changes = 1;
					break;
				}

				//  If we reach end-of-file, the files are the same.  
				if (filevec[0].buffered_chars==0) // therefore: filevec[1].buffered_chars==0
				{
					changes = 0;
					break;
				}	

				//	If buffers have different contents, the files are different.
				if (memcmp (filevec[0].buffer,
							filevec[1].buffer,
							filevec[0].buffered_chars) != 0)
				{
					changes = 1;
					break;
				}

				//	Files appear identical so far...
				//	Prepare to loop again for the next pair of buffers.
				filevec[0].buffered_chars = filevec[1].buffered_chars = 0;
			}
		}
		
		briefly_report (changes, filevec);

		if (bin_status != NULL)
			*bin_status = (changes != 0 ? -1 : 1);
	}
	else
	{
		//  Allocate vectors for the results of comparison:
		// a flag for each line of each file, saying whether that line
		// is an insertion or deletion.
		// Allocate an extra element, always zero, at each end of each vector.  
		
		size_t s = filevec[0].buffered_lines + filevec[1].buffered_lines + 4;
		filevec[0].changed_flag = (char *)xmalloc (s);
		bzero (filevec[0].changed_flag, s);
		filevec[0].changed_flag++;
		filevec[1].changed_flag = filevec[0].changed_flag
			+ filevec[0].buffered_lines + 2;
		
		//  Some lines are obviously insertions or deletions
		// because they don't match anything.  Detect them now, and
		// avoid even thinking about them in the main comparison algorithm.  
		
		discard_confusing_lines (filevec);
		
		//  Now do the main comparison algorithm, considering just the
		// undiscarded lines.  
		
		xvec = filevec[0].undiscarded;
		yvec = filevec[1].undiscarded;
		diags = filevec[0].nondiscarded_lines + filevec[1].nondiscarded_lines + 3;
		fdiag = (int *) xmalloc (diags * (2 * sizeof (int)));
		bdiag = fdiag + diags;
		fdiag += filevec[1].nondiscarded_lines + 1;
		bdiag += filevec[1].nondiscarded_lines + 1;
		
      /* Set TOO_EXPENSIVE to be approximate square root of input size,
	     bounded below by 4096.  4096 seems to be good for circa-2016 CPUs 
	  */
        too_expensive = 1;
        for (i = filevec[0].nondiscarded_lines + filevec[1].nondiscarded_lines;
	         i != 0; i >>= 2)
		  too_expensive <<= 1;
        too_expensive = max (4096, too_expensive);

		files[0] = filevec[0];
		files[1] = filevec[1];
		
		compareseq (0, filevec[0].nondiscarded_lines,
		  0, filevec[1].nondiscarded_lines, no_discards);
		
		free (fdiag - (filevec[1].nondiscarded_lines + 1));
		
		//  Modify the results slightly to make them prettier
		// in cases where that can validly be done.  
		
		shift_boundaries (filevec);
		
		//  Get the results of comparison in the form of a chain
		// of `struct change's -- an edit script.  
		
#if 0
		if (output_style == OUTPUT_ED)
			script = build_reverse_script (filevec);
		else
#endif
			script = build_script (filevec);
		
		//  Set CHANGES if we had any diffs.
		// If some changes are ignored, we must scan the script to decide.  
		if (ignore_blank_lines_flag)
		{
			struct change *next = script;
			changes = 0;
			
			while (next)
			{
				struct change *thisob, *end;
				int first0, last0, first1, last1, deletes, inserts;
				
				//  Find a set of changes that belong together.  
				thisob = next;
				end = find_change (next);
				
				//  Disconnect them from the rest of the changes, making them
				// a hunk, and remember the rest for next iteration.  
				next = end->link;
				end->link = NULL;
				
				//  Determine whether thisob hunk is really a difference.  
				analyze_hunk (thisob, &first0, &last0, &first1, &last1,
					&deletes, &inserts, files);
				
				//  Reconnect the script so it will all be freed properly.  
				end->link = next;
				
				if (deletes || inserts)
					changes = 1;

			}
		}
		else
		{
			changes = (script != NULL);
		}

		/* WinMerge moved block support */
		if (bMoved_blocks_flag)
		{
			moved_block_analysis(&script, filevec);
		}
		
		if (no_details_flag)
			briefly_report (changes, filevec);
		else
		{
			if (changes==0 && ignore_blank_lines_flag)
			{
				// determined that there were no nontrivial changes after considering flags
			}
			else if (changes == 0)
			{
				// determined that there were no nontrivial changes after considering flags
			}
			else if (changes || ! no_diff_means_no_output)
			{
				//  Record info for starting up output,
				// to be used if and when we have some output to print.  
				setup_output (files[0].name, files[1].name, depth);
				
				/*switch (output_style)
				{
				case OUTPUT_CONTEXT:
					print_context_script (script, 0);
					break;
					
				case OUTPUT_UNIFIED:
					print_context_script (script, 1);
					break;
					
				case OUTPUT_ED:
					print_ed_script (script);
					break;
					
				case OUTPUT_FORWARD_ED:
					pr_forward_ed_script (script);
					break;
					
				case OUTPUT_RCS:
					print_rcs_script (script);
					break;
					
				case OUTPUT_NORMAL:
					print_normal_script (script);
					break;
					
				case OUTPUT_IFDEF:
					print_ifdef_script (script);
					break;
					
				case OUTPUT_SDIFF:
					print_sdiff_script (script);
				}
				
				finish_output ();*/
			}
		}
		
		//free (filevec[0].undiscarded);
		
		//free (filevec[0].changed_flag - 1);
		
		//for (i = 1; i >= 0; --i)
		//	free (filevec[i].equivs);
		
		//for (i = 0; i < 2; ++i)
		//	free (filevec[i].linbuf + filevec[i].linbuf_base);
		
		
		/*cleanup the script
		for (e = script; e; e = p)
		{
			p = e->link;
			free (e);
		}*/
		
		if (! ROBUST_OUTPUT_STYLE (output_style))
			for (i = 0; i < 2; ++i)
				if (filevec[i].missing_newline)
				{
					error ("No newline at end of file %s", filevec[i].name, "");
					changes = 2;
				}
    }
	
	//if (filevec[0].buffer != filevec[1].buffer)
	//	free (filevec[0].buffer);
	//free (filevec[1].buffer);
	
	return script;
}

void cleanup_file_buffers(struct file_data fd[])
{
	int i;
	free (fd[0].undiscarded);
	
	if (fd[0].changed_flag != NULL)
		free (fd[0].changed_flag - 1);
	
	for (i = 1; i >= 0; --i)
		free (fd[i].equivs);
	
	for (i = 0; i < 2; ++i)
		free ((void *)(fd[i].linbuf + fd[i].linbuf_base));

	if (fd[0].buffer != fd[1].buffer)
		free (fd[0].buffer);
	free (fd[1].buffer);
}
